a2-(b-c)2 factorise it
Answers
Answered by
16
Answer:
a²-(b-c)²=(a+b-c)(a-b+c)
Explanation:
Factorising a²-(b-c)²
_______________________
we know the algebraic identity:
a2-b2 is equal to (a+b)*(a-b)
_______________________
= [a+(b-c)][a-(b-c)]
=(a+b-c)(a-b+c)
Therefore,
a²-(b-c)²=(a+b-c)(a-b+c)
Answered by
5
Answer:
a^2-(b-c)^2
Step-by-step explanation:
a^2-(b-c)^2 (put (a^2-b^2))
(a-b+c) (a+b-c) answer..
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