Question

a2+b2=10^2-48 find a and b​

Answer 1

Answer:

a=4 and b=6.

Step-by-step explanation:

Given : Expression a^2+b^2=10^2-48a

2

+b

2

=10

2

−48

To find : The value of a and b?

Solution :

First we solve the expression,

a^2+b^2=10^2-48a

2

+b

2

=10

2

−48

a^2+b^2=100-48a

2

+b

2

=100−48

a^2+b^2=52a

2

+b

2

=52

Now, we have to write 52 in such a way that it form of sum of square terms.

Square terms are

1,4,9,16,25,36,49 are all less than 52.

52=16+3652=16+36

52=4^2+6^252=4

2

+6

2

Substitute,

a^2+b^2=4^2+6^2a

2

+b

2

=4

2

+6

2

On comparing the value of a is 4 and b is 6.

Therefore, a=4 and b=6.