Question

a2+b2=13 and ab=6 find a+b

Answer 1

$x^{2} + y^{2}= 13$

ab= 6

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$(a+b)^{2}$ $= a^{2} + b^{2} + 2ab$

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But, the values of ab and $a^{2} + b^{2}$  is given,

So 

$(a+b)^{2} = a ^{2} + b^{2} + 2ab$


putting the given values



[tex](a+b)^{2} = 13 + 2(6) [/tex]


$(a+b)^{2}$ = 13+ 12

$(a+b)^{2}$= 25

(a+b) = $\sqrt{25}$


a+b =5



i hope this will help you


-by ABHAY

Answer 2

Answer:

5 is the required value of (a + b ).

Step-by-step explanation:

Explanation:

Given , $a^{2} +b^{2}$ = 13 and ab = 6

As we know that  formula  $(a+b)^{2}$ is the algebraic identity used to find the square of the sum of two numbers.

Step1:

From the formula we have ,

$(a+b)^{2}$ = $a^{2} + b^{2} + 2ab$

⇒$(a+b)^{2}$ = $(a^{2} + b^{2} ) + 2ab$

Now , put the value of $a^{2} +b^{2}$ = 13 and ab = 6 in the algebraic equation,

⇒$(a+b)^{2}$ = 13 + 2× 6

⇒$(a+b)^{2}$ = 25

⇒ a + b = $\sqrt{25} = 5$ .

Final answer:

Hence , value of (a + b) is 5.

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