Question

(a²-b²)² + (a²+b²)²

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Answer 1

Heya✌

Q u e s t i o n:

• (a²-b²)²+(a²+b²)²

S o l u t i o n:

As we know (a+b)²=a²+b²+2ab and (a-b)= a²+b²-2ab

Therefore,

(a²-b²)²+(a²+b²)²

= [(a²)²+(b²)²–2(a²)(b²)]+[(a²)²+(b²)²+2(a²)(b²)]

=(a⁴+b⁴–2a²b²)+(a⁴+b⁴+2a²b²)

=a⁴+b⁴-2a²b²+a⁴+b⁴+2a²b²

=2a⁴+2b⁴

=2(a⁴+b⁴)

A n s w e r = 2(a⁴+b⁴)

Answer 2

Answer:

$2 {a}^{4} + 2 {b}^{4}$

Step-by-step explanation:

(a^2 - b^2) + (a^2 +b^2)

a^4 +b^4 - 2a^2 b^2 + a^4 +b^4 +2a^2 b^2

2a^4 + 2b^4

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