Math, asked by abhipshabhandari7, 7 months ago

(a2-b2)2-a2b2
factorization process please

Answers

Answered by shrinkhal03
0

Answer:

a^4-b^4-3a^2b^2

Step-by-step explanation:

using identity (a-b)^2=a^2+b^2-2ab open the first term and you ill get

a^4+b^4-2a^2b^2-a^2b^2  

And then you will get the answer.

I hope you understood.

Answered by abhipsha02755
1

Answer:

Step-by-step explanation:

a^4-b^4-3a^2b^2

Step-by-step explanation:

using identity (a-b)^2=a^2+b^2-2ab open the first term and you ill get

a^4+b^4-2a^2b^2-a^2b^2  

And then you will get the answer.

I hope you understood.

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