Math, asked by drami200729, 2 months ago

a²+b²+2 [ab + bc + ca]

Answers

Answered by akshikatiwari06

4

= (a + b)2 + 2bc + 2ca

= (a + b)2 + 2c (b + a)

or (a + b)2 + 2c (a + b)

Taking (a + b) common

= (a + b)(a + b + 2c )

∴ a2 + b2 + 2 (ab + bc + ca) = (a + b)(a + b + 2c)

Answered by Anonymous

6

Answer:

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