a²+b²+2ab, 3a²-2ab + 5b²,Subtract the given terms.
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Solution :
Given two expressions are
a² + b² + 2ab and 3a² - 2ab + 5b²
Now ,
Subtracting second expression from
first , we get
a² + b² + 2ab - ( 3a² - 2ab + 5b² )
= a² + b² + 2ab - 3a² + 2ab - 5b²
= a² - 3a² + b² - 5b² + 2ab + 2ab
= ( 1 - 3 )a² + ( 1 - 5 )b² + ( 2 + 2 )ab
= -2a² - 4b² + 4ab
••••
Given two expressions are
a² + b² + 2ab and 3a² - 2ab + 5b²
Now ,
Subtracting second expression from
first , we get
a² + b² + 2ab - ( 3a² - 2ab + 5b² )
= a² + b² + 2ab - 3a² + 2ab - 5b²
= a² - 3a² + b² - 5b² + 2ab + 2ab
= ( 1 - 3 )a² + ( 1 - 5 )b² + ( 2 + 2 )ab
= -2a² - 4b² + 4ab
••••
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