Question

(a²+b²+2ab)-(a²+b²-2ab)​

Answer 1

$(a^2+b^2+2ab)-(a^2+b^2-2ab )\\\\(a^2+b^2+2ab) = (a+b)^2 \\\\(a^2+b^2-2ab ) = (a-b)^2\\\\=>(a+b)^2 - (a-b)^2 \\\\a^2-b^2 = (a+b)(a-b)\\\\here \ a = a+b \ , b = a-b\\\\(a+b+a-b) (a+b-a-b) = 2a * 0 = 0 \\\\answer = 0 \\\\hope \ it \ helps \ !!$

Answer 2

Answer:

$\huge\mathcal\red{ 4ab}$

Step-by-step explanation:

$( {a}^{2} + {b}^{2} + 2ab \: ) - ( {a}^{2} + {b}^{2} - 2ab) \\ \\ {a}^{2} + {b}^{2} + 2ab - {a}^{2} - {b}^{2} + 2ab \\ \\ {a}^{2} - {a}^{2} + {b}^{2} - {b}^{2} + 2ab \: + 2ab \\ \: \\ 0 + 0 + 4ab \\ \\ 4ab \:$

$\fbox\green{Hence the Answer is 4ab}$