Math, asked by roychoton051, 8 months ago

a²-b²-2bc-c²/a²+b²+2ab-c²=?​

Answers

Answered by Anonymous
2

Answer:

= a²- (b²+ 2bc +c²) / (a²+b²- 2ab) - c²

= a² - (b + c)² / (a- b)² -c²

=(a+ b+ c)(a- b - c) / (a - b + c)(a - b - c)

=a+b+c / a-b+c

Hope it helps

By formula of

(a²-b²)

Similar questions