Question

(a²-b²)³+(b²-c²)³+(c²-a²)³​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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Given (a²-b²)³+(b²-c²)³+(c²-a²)³=3(a+b)(b+c)(c+a)(a-b)(b-c)(c-a)

Consider LHS:(a²-b²)³+(b²-c²)³+(c²-a²)³

We know that if x + y + z =0 then x3 + y3 + z3 = 3xyz

Here x = a²-b², y = b²-c² and z = c²-a²

a²-b² + b²-c² + c²-a² = 0

Hence (a²-b²)³+(b²-c²)³+(c²-a²)³ = 3(a²-b²)(b²-c²)(c²-a²)³

= 3(a + b)(a − b)(b + c)(b − c)(c + a)(c − a)

= 3(a + b)(b + c)(c + a)(a − b)(b − c)(c − a)

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