Question

A2+b2=34 and ab=12 find 3(a+b)2+5(a+b)2

Answer 1

Answer:

$3(a+b)^2+5(a+b)^2=464$

Step-by-step explanation:

Formula used:

$(a+b)^2=a^2+b^2+2ab$

Given:

$a^2+b^2=34$

$ab=12$

consider,

$(a+b)^2=a^2+b^2+2ab$

$(a+b)^2=34+2(12)$

$(a+b)^2=34+24$

$(a+b)^2=58$

Now,

$3(a+b)^2+5(a+b)^2$

$=8(a+b)^2$

$=8(58)$

$=464$