a2 + b2 - 4a - 4b + 8 = 0
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(a-2)^2+(b-2)^2=0
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0
Proceed by rearranging the terms
a²-4a+b²-4b+(4+4) =0
a²-4a+2²+b²-4b+2²=0
(a-2)²+(b-2)² = 0
(a,b) = (2,2)
a²-4a+b²-4b+(4+4) =0
a²-4a+2²+b²-4b+2²=0
(a-2)²+(b-2)² = 0
(a,b) = (2,2)
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