a² + b² - 4ac + 4c²
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Answer:
Factor of a² + b² - 4ac + 4c² is (a²+c²+b²)(a²-c²-b²)
Step-by-step explanation:
= a²+b²-4ac+c²
= (a²-4ac+c²)+b²
= [(a)²-(2×a×c)+(c)²]+b²
= (a²-c²)+b²
Using the formula a²-b² = (a+b)(a-b)
= (a²+c²+b²)(a²-c²-b²)
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