a2-b2-4c2+4d2-4(ad-bc)
Answers
Answered by
8
Given -
a² - b² - 4c² + 4d² - 4 ( ad - bc )
= a² - b² - 4c² + 4d² - 4ad + 4bc
Rearranging
= a² + 4d² - 4ad - b² - 4c² + 4bc
= a² + 4d² - 4ad - ( b² + 4c² - 4bc )
{ Using identity
a² + b² - 2ab = ( a + b )² }
= ( a )² + ( 2d )² - ( 2 ) ( a ) ( 2d ) - [ ( b )² + ( 2c )² - ( 2 ) ( b ) ( 2c ) ]
= ( a - 2d )² - ( b - 2c )²
^^"
a² - b² - 4c² + 4d² - 4 ( ad - bc )
= a² - b² - 4c² + 4d² - 4ad + 4bc
Rearranging
= a² + 4d² - 4ad - b² - 4c² + 4bc
= a² + 4d² - 4ad - ( b² + 4c² - 4bc )
{ Using identity
a² + b² - 2ab = ( a + b )² }
= ( a )² + ( 2d )² - ( 2 ) ( a ) ( 2d ) - [ ( b )² + ( 2c )² - ( 2 ) ( b ) ( 2c ) ]
= ( a - 2d )² - ( b - 2c )²
^^"
Answered by
1
Answer
(a-2d+b-2c) (a-2d-b+2c)
Solution:
Q. a²-b²-4c²+4d²-4(ad-bc)
= a²- b²- 4c² + 4d²- 4ad + 4bc
= a² + 4d² - 4ad - b² - 4c² + 4bc
= a² + 4d² - 4ad - (b² + 4c² - 4bc)
= a²+ (2d)² - 2(a)(2d) - {(b)²+(2c)²-2(b)(2c)}
= (a - 2d)² - (b - 2c)²
= (a - 2d - b + 2c) (a - 2d + b - 2c)
Similar questions