Question

a2+b2=7ab then prove the 2(a-b)= log5+log a+log b

Answer 1

Step-by-step explanation:

1. 2log5+2loga+7logab
2. log5²+loga²+logab7
3. log25+loga+log7ab

Answer 2

Answer:

Step-by-step explanation: Given that a2+b2=7ab

                  adding 2ab on both sides . we get

                        a2+b2+2ab=9ab    

                    it can be written as (a+b)2  

then               (a+b)2= 3^(2) ab

                            applying log on both sides we get

                        log(a+b)^2 = log3(^2)ab

                            so,

                           2log(a+b)=log a+log b+ 2log3      [since log m^n= n log m]

          hence proved

I HOPE THIS WILL HELP YOU VERY WELL