Question

a² + b² = 7b and b² + (2b-a)² = 7²
find (a - b)² .

Solve it
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Answer 1

Answer:

(a - b)² = 1.27825

Step-by-step explanation:

a² + b²-7b

270

4.0

a²=7b-b²

a = √(7b-b²)

Also given :

b²+(2b-a)²=7²

→ b²+4b²+ a²-4ab=7²

4b²+7b-7²-4ab [a³ + b³ = 7b]

Putting value of a = √( 7b-b²)

4b²+7b-7²=4b √(7b-b²)

Squaring on both side:

(4b²+7b-49)² = (4b √ (7b-b²))

(16 b* +49 b² +49 +56 b³-49 x 14 b-49 x 8 b²)=16 b² (7 b --6²)

16 b¹ +49 b +49 +56 b³-49 x 14 b-49 x 8 b²)=112 b³-16

32 b* -56 b³ +2401 +49 b²-686 b-392 b² = 0

32 b56 b² 343 b²-686 b +2401-0

On solving bi-quadratic equation we get: