Question

a²+b² = 88, ab =6find of the value ,a³+b³​

Answer 1

Step-by-step explanation:

hope you understand it.

Answer 2

Answer:

a^2+b^2=88

ab=6

a^2+b^2=88

=> (a+b)^2-2ab=88

=> (a+b)^2=88+2ab

=> (a+b)^2=88+2.6=88+12=100

=> (a+b)^2=(10)^2

=> a+b=10

a^3+b^3

=(a+b)(a^2-ab+b^2)

=(a+b)(a^2+b^2-ab)

=10(88-6)

=10.82

=820