Math, asked by subhajit93, 1 year ago

a2+b2+8a+6b+25=0,a3+b3=???

Answers

Answered by adityasahu73
0
the answers of this question is ab4
Answered by TheRevenant01
0

Break 25 into 16 and 9

(a²+8a+16)+(b²+6b+9) = 0

(a+4)²+(b+3)²= 0

(a+4)=(b+3)=0

a=-4 , b = -3

a³+b³ = -91

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