Question

(a²-b²)(a²+b²)+(b²-c²)(b²+c²)+(c²-a²)(c²+a²) =0​

Answer 1

Answer:

0 its true

Step-by-step explanation:

a⁴+a²b²-b²a²-b⁴+b⁴+b²c²-c²b²-c⁴+c⁴c²a²-a²c²-a⁴=0

Answer 2

Answer:

$lhs$

Step-by-step explanation:

$|a^{2} - b^{2} | + |b^{2} - c^{2} | + |c^{2} - a^{2} |$

$a^{2}- b^{2} + b^{2} - c^{2} + c ^{2} - a^{2}$

$0$

$rhs$