(a²+b²)(a²-b²)+b²+ c²)+ c²+a²) (c²-a²)
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Answer:
a^2b^2-a^2c^2+a^2b^2-b^2c^2+a^2c^2-b^2c^2
=(ab)^2-(ac)^2+(ab)^2-(bc)^2+(ac)^2-(bc)^2
=2(ab)^2-2(bc)^2
Step-by-step explanation:
hope it helps
Answered by
0
Answer:
a^2b^2-a^2c^2+a^2b^2-b^2c^2+a^2c^2-b^2c^2
=(ab)^2-(ac)^2+(ab)^2-(bc)^2+(ac)^2-(bc)^2
=2(ab)^2-2(bc)^2
Step-by-step explanation:
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