Math, asked by jill4171, 2 days ago

(a²+b²)(a²-b²)+b²+ c²)+ c²+a²) (c²-a²)​

Answers

Answered by Anonymous
0

Answer:

a^2b^2-a^2c^2+a^2b^2-b^2c^2+a^2c^2-b^2c^2

=(ab)^2-(ac)^2+(ab)^2-(bc)^2+(ac)^2-(bc)^2

=2(ab)^2-2(bc)^2

Step-by-step explanation:

hope it helps

Answered by vnsn2811
0

Answer:

a^2b^2-a^2c^2+a^2b^2-b^2c^2+a^2c^2-b^2c^2

=(ab)^2-(ac)^2+(ab)^2-(bc)^2+(ac)^2-(bc)^2

=2(ab)^2-2(bc)^2

Step-by-step explanation:

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