a²+b²/a³-b³ what is the value of now those a+b=8 and a-b=2
Answers
Answer:
34 and 98
Step-by-step explanation:
For this question first we have to perform simultaneous linear equations to get the values and for that
you can choose any one method from two methods(i.e.; elimination method or substitution method).
Here, i am using substitution method:
Step 1- If a+b=8 then a=8-b;
Step 2- Substituting the value of 'a' in a-b=2 equation(i.e; 8-b-b=2)
Step 3- On solving 8-b-b=2; we get b as:-
=>8-2b=2;
=>8-2=2b;
=>6=2b;
=>6/2=b;
=>3=b or b=3.
therefore, value of b is 3.
Step 4- Substituting the value of 'b' in a=8-b equation to constant value of 'a'
a=8-3
a=5.
Step 5- a*a
=> 5*5
=>25
Similarly with b
b*b
=> 3*3
=> 9
Step 6- Now we have all the values to get the values of (a*a+b*b) and ab
1) a*a+b*b
=>25+9
=>34
Therefore value of (a*a+b*b)=34
2) a³-b³
=>125-27
=>98
So, the answers according the question is 34 and 98.
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