(a2 + b2) and a2 - b2 ehich one is common factore
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Answer:
ab(a
2
+b
2
−c
2
)−bc(c
2
−a
2
−b
2
)+ca(a
2
+b
2
−c
2
)
=ab(a
2
+b
2
−c
2
)+bc(−c
2
+a
2
+b
2
)+ca(a
2
+b
2
−c
2
)
=(a
2
+b
2
−c
2
)[ab+bc+ca]
Step-by-step explanation:
Factorise by taking out the common factors :
ab(a
2
+b
2
−c
2
)−bc(c
2
−a
2
−b
2
)+ca(a
2
+b
2
−c
2
)
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