Question

a2+b2-c2=0, then find the value of a6+b6-c6/a2b2c2​

Answer 1

Answer:

-3

Explanation:

It is given that ,

a²+b²-c² =0

=> a²+b² = c² -----(1)

On cubeing both sides,we get

=> (a²+b²)³ = (c²)³

**********************

We know the algebraic identity:

(x+y)³ = x³+y³+3xy(x+y)

**********************

(a²)³+(b²)³+3a²b²(a²+b²)=c^6

=> a^6+b^6+3a²b²c²=c^6

[ from (1)]

=> a^6+b^6+c^6 =-3a²b²c²

=> (a^6+b^6+c^6)/(a²b²c²)=-3

••••

Answer 2

Answer:

$\huge \bold \color{pink}{answer}$

Answer is = -3

Step-by-step explanation:

Full solution step in attachment

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