Question

a² +b²+c²=14 find ab+bc+ca​

Answer 1

Heya!

Here is ur answer...

Given,

a+b+c = 4

a²+b²+c² = 14

Now,

(a+b+c)² = a²+b²+C² +2ab+2bc+2ac

4² = 14+2(ab+bc+ac)

16 = 14+2(ab+bc+ac)

16-14 = 2(ab+bc+ac)

2 = 2(ab+bc+ac)

ab+bc+ac = 2/2

ab+bc+ac = 1

Hope it helps!

Answer 2

Given,

a + b + c = 4

a² + b² + c² = 14

We know that,

(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

Substitute the values in their respective areas.

(4)² = 14 + 2(ab + bc + ca)

16 = 14 + 2(ab + bc + ca)

16 - 14 = 2(ab + bc + ca)

2 = 2(ab + bc + ca)

Transport 2 into LHS.

2/2 = ab + bc + ca

ab + bc + ca = 1

Therefore, ab + bc + ca = 1