Question

a²+b²+c² = 2(a-b-c)-3 then find the value of a-b-c

Answer 1

A^2+b^2+c^2=2(a-b-c)-3
a^2+b^2+c^2+3/2=a-b-c
i hope u understand
i think it is right ans

Answer 2

a²+b²+c² -2a +2b+2c +3= 0

a²-2a +1 + b²+2b+1 + c^2 +2c +1. = 0

(a-1)^2 + (b+1)^2 + (c +1 )^2 = 0

sum of the square of 3 non zero numbers can not be zero ...
here all number should be individually equal to zero
a-1 =0 .... a=1
b+1=0 ....b= -1
c+1 =0 ... c = -1


value of a-b-c = 1+1+1=3