à²+b²+c²+2(ab+bc+ca)
a=3,b= -5,c=3
its very urgent.....with explanation.
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Answer:
putting the values of a,b,c you will get 1
similarly by identity (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
(3-5+3)^2=(1)^2=1 only
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