(a2+b2-c2)^2
simplify this
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Now,
2(ab+cd)−a2−b2+c2+d2
=(c2+2cd+d2)−(a2−2ab+b2)
=(c+d)2−(a−b)2
=(c+d+a−b)(c+d−a+b)
Now,
2(ab+cd)−a2−b2+c2+d2
=(c2+2cd+d2)−(a2−2ab+b2)
=(c+d)2−(a−b)2
=(c+d+a−b)(c+d−a+b)
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