(a²+b²+c²) = 20
(a+b+c) = 0
(ab+bc+ca) = ?
99 points.....
kakkar6644:
Deepas do u know the answer?
Answers
Answered by
5
Squaring the given equation
(a+b+c)^2 = 0^2
a^2+b^2+c^2+2ab+2bc+2ca = 0
According to given 1st equation,
20+2(ab+bc+ca) = 0
ab+bc+ca = -20/2 = -10
Answered by
1
a+b+c=0
square on both sides, a²+b²+c²+2ab+2bc+2ca=0²=0
substituting the value of a²+b²+c²=20,
20 + 2(ab+bc+ca) = 0
so ab+bc+ca = -20/2 =-10
square on both sides, a²+b²+c²+2ab+2bc+2ca=0²=0
substituting the value of a²+b²+c²=20,
20 + 2(ab+bc+ca) = 0
so ab+bc+ca = -20/2 =-10
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