Question

a²+b²+c²=20 and a+b+c= 0, find ab+bc+ca​

Answer 1

Answer:

(a+b+c)²=a²+b²+c²+2(ab+bc+ac)

by putting given value we get

0²=20+2(ab+bc+ac)

(ab+bc+ac)=-20/2

= -10

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Answer 2

Answer:

-10

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

0^2=20+2(ab+bc+ca)

-20=2(ab+bc+ca)

-20/2=ab+bc+ca

-10=ab+bc+ca

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