a2 +b2+c2=20व a+b+c=0तोab+bc+ca=?
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Answer:
ab+bc+ca = -10
Step-by-step explanation:
a²+b²+c² = 20 ---(1)
a+b+c = 0 ----(2)
/* On Squaring both sides of the equation, we get
=> (a+b+c)² = 0²
=> a²+b²+c²+2ab+2bc+2ca=0
=> 20+2(ab+bc+ca) = 0
=> 2(ab+bc+ca) = -20
=> ab+bc+ca = (-20)/2
=> ab+bc+ca = -10
Therefore,
ab+bc+ca = -10
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