Math, asked by saratdolai992, 7 months ago

a2+ b2 + c2 =251 , 1/2(ab+ bc+ ca) =3, then find a+ b+ c​

Answers

Answered by likitha656
1

Answer:

 \sqrt{ \frac{754}{3} }

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

  • 1/2(ab+bc+ca)=3
  • 3[2(ab+ba+ca)]=1
  • 2(ab+bc+ca)=1/3

(a+b+c)²=251+1/3

(a+b+c)²=754/3

a+b+c=

 \sqrt{ \frac{754}{3} }

.

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