a2+ b2 + c2 =251 , 1/2(ab+ bc+ ca) =3, then find a+ b+ c
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Answer:
Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
- 1/2(ab+bc+ca)=3
- 3[2(ab+ba+ca)]=1
- 2(ab+bc+ca)=1/3
(a+b+c)²=251+1/3
(a+b+c)²=754/3
a+b+c=
.
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