Question

A²+b²+c²=26 and ab+bc+ca=19 find value of a+b+c

Answer 1

Answer:

8

Step-by-step explanation:

(a+b+c) whole square=A²+b²+c²+2(ab+bc+ca)

root of 26+2(19)=a+b+c

root of 26+38=a+b+c

root of 64= a+b+c

a+b+c= 8

Hope it helps!

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