Question

a2-b2-c2-2ab-2bc-2ac If a=2,b=-2,c=1​

Answer 1

Step-by-step explanation:

by substituting we get

Answer 2

Answer:

${a}^{2} - {b}^{2} - {c}^{2} - 2ab - 2bc - 2ca \\ \\ where \: a = 2 \: \: \: b = - 2 \: \: \: c = 1 \\ \\ now \: put \: in \: the \\ \: given \: equation \\ \\ ({2})^{2} - ( { - 2)}^{2} - ( {1)}^{2} - 2(2)( - 2) - 2( - 2)(1) - 2(2)(1) \\ \\ 4 - 4 - 1 + 8 + 4 - 4 \\ \\ - 1 + 8 \\ \\ 7$