Question

a2+b2+c2=50
ab+bc+ca=47
Find a+b+c

Answer 1

⭐Solution ⭐

➡Given here

a²+b²+c²=50.....(1)

ab+bc+ca= 47....(2)

find here

(a+b+c)=❓

Now,

we know,

(a+b+c)²= a²+b²+c²+2(ab+bc+ca)

keep value ,

(a+b+c)²= (50)+2(47)

= 50+94

= 144

so,

(a+b+c)= ±√(144)

= ±12

⏩Hopes its help's u

➡Marks Brainliest.

Answer 2

$\huge\underline\mathfrak\green{Solution}$

( a + b + c) ² = a² + b² + c² + 2 ( ab + bc + ca )

( a + b + c ) ² = 50 + 2 × 47 = 144

Therefore a + b + c = ±12

Thanks!! ✨❤