Question

a²+b²+c²=74 and ab+bc+ac=61. find a+b+c​

Answer 1

Answer:

It is identity

Step-by-step explanation:

Answer 2

Step-by-step explanation:

a^2+b^2+c^2=74

ab+bc+ca=61

$(a + b + c) { }^{2} = a ^{2} + b ^{2} + c ^{2} + 2(ab + bc + ca)$

(a+b+c)^2=74+2(61)

=74+122

=196

a+b+c= 14