Question

A2+b2+c2=9 and ab=4 find the value of 3(a+b)2-(a-b)2

Answer 1

a+b=6

a-b=4

By adding the above two equations , we get a=5 ,

When we substitute a=5 , in one of the equations we get b=1

a=5 and b=1

a.a + b.b = 5.5 + 1.1

a2 + b2 = 26

Answer 2

a + b=6

a - b=4

a + b + a - b = 6 + 4

2a = 10

a = 5

a + b = 6

5 + b = 6

b = 1

a = 5 and b = 1

a * a + b * b = 5 * 5 + 1* 1

a ^ 2 + b^ 2 = 25 + 1 = 26

hope it helps you

pls mark as brainliest

a2 + b2 = 26