Question

(A²+ B²+ C² - AB - BC-CA)(A+B+C)​

Answer 1

Answer:

a2 + b2 + c2 – ab – bc – ca = 12{2a2 + 2b2 + 2c2 – 2ab – 2bc – 2ca}...

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Answer 2

Answer:

$a^3 + b^3 + c^3 - 3abc$

Step-by-step explanation:

$(a+b+c)(a^2+b^2+c^2 - ab - bc - ca)$

$a(a^2 + b^c + c^2 - ab - bc - ca) + b (a^2 + b^2 + c^2 - ab - bc - ca) + c (a^2 + b^2 + c^2 - ab - bc - ca)$

$(a^3 + ab^2 + ac^2 - a^2b - abc -ca^2) + (a^2b + b^3 + bc^2 - ab^2 - b^2c - abc) +(a^2c + b^2c + c^3 - abc - bc^2 - c^2a)$

$a^3 + b^3 + c^3 - 3abc$

Solution: $a^3 + b^3 + c^3 - 3abc$

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