Question

a2 +b2 +c2=ab+bc+ca then (a+b)/2c​

Answer 1

Answer:

(a+b)/2c = 1

Step-by-step explanation:

So, take your equation as ,

a²+b²+c²-ab-bc-ca = 0

multiply both side by 2,

2a²+2b²+2c²-2ab-2bc-2ca = 0

Now ,

(a²+b²-2ab)+(b²+c²-2bc)+(c²+a²-2ca) = 0

(a-b)²+(b-c)²+(c-a)² = 0

it means,

a-b=0, b-c =0, c-a=0

a=b=c

so, your answer is

a+b/2c = 2c/2c = 1

hope you will satisfy with my answer thanks