Question

a2(b2-c2) +b2(c2-a2) +c2(a2-b2)​

Answer 1

Answer:

ab(a2 + b2 - c2) - bc (c2 - a2 - b2) + ca (a2 + b2 - c2)

= ab(a2 + b2 - c2) + bc (a2 + b2 - c2) + ca (a2 + b2 - c2)

= (a2 + b2 - c2)(ab + bc + ca)

Step-by-step explanation:

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Answer 2

Answer:

0

Step-by-step explanation:

a2(b2-c2) +b2(c2-a2) +c2(a2-b2)

= a²b²-a²c²+b²c²-b²a²+c²a²-c²b²

So if we subtarct or cancel terms in the Equation we get '0'

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