Question

(a²-b²-c²+d²)² - 4(ab-bc)²​

Answer 1

Answer:

a² - b² - c² - 2(ad- bc)

= a² - b² - c² + d² - 2ad + 2bc

= a² + d² - 2ad - b² -c² + 2bc

= (a² + d² - 2ad) - (b² + c² - 2bc)

= (a-d)² - (b + c)²

= [( a - d) + (b + c)][(a - d) - (b + c)]

= (a - d + b + c)(a - d - b - c)

Or

= (a + b + c - d)(a - b - c - d)

Step-by-step explanation:

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