Question

(a2-b2) (c2-d2) - 4abcd​

Answer 1

Answer:

( ac - bd - ad - bc ) ( ac - bd + ad + bc )

Step-by-step explanation:

I am guessing that what is actually required is to factorize this.  Hope that's right!

Proceeding with that in mind...

( a² - b² ) ( c² - d² ) - 4abcd

= a²c² - a²d² - b²c² + b²d² - 4abcd

= ( a²c² + b²d² - 2abcd ) - ( a²d² + b²c² + 2abcd )

= ( ac - bd )² - ( ad + bc )²

= [ ( ac - bd ) - ( ad + bc ) ] [ ( ac - bd ) + ( ad + bc ) ]       ( used x²-y²=(x-y)(x+y) )

= ( ac - bd - ad - bc ) ( ac - bd + ad + bc )

Hope this helps!

Answer 2

Step-by-step explanation:

$(p 2 - q2 = (p - q)(p + q)$