Math, asked by syedamaseera77, 2 months ago

(a²- b²) (c² - d²) - 4abcd​

Answers

Answered by Pritthiraj
4

Answer:

(ac - bd + ad + bc) (ac - bd - ad - bc)

Step-by-step explanation:

(a²- b²) (c²- d²) - 4abcd

= a²c² - a²d² - b²c² + b²d²- 4abcd

= a²c² -2abcd + b²d² - a²d² -2abcd -b²c²

= a²c² -2abcd + b²d² -(a²d² +2abcd +b²c²)

= (ac - bd)² - (ad + bc)²

= (ac - bd + ad + bc) (ac - bd - ad - bc)

hope u understand.... :)

Similar questions