Question

(a²-b²) (c²-d²) -4abcd​

Answer 1

Answer:

a²c² - a²d² -b²c² +b²d² - 4abcd

a²c² - a²d² -b²c² +b²d² -2abcd - 2abcd

a²c² + b²d² - 2abcd - ( a²d² + b²c² + 2abcd)

(ac - bd) ² - ( ad + bc)²

(ac - bd + ad + bc) ( ac - bd - ad - bc)

[c(a+b) + d (a -b) ] [ c (a-b) -d(a+b)]

Step-by-step explanation:

Hope this answer will help you.

Thank you

Please mark me as a brainliest.