Math, asked by RudranshVashistha, 6 months ago

√a²-√b² upon √a²+√b²/√a²+√b²-b upon a-√a²-√b²

Answers

Answered by birendrapaswanbs1982
0

Answer:

Solution: a=

3

+

2

3

2

b=

3

2

3

+

2

ab=

3

×

2

3

2

×

3

2

3

+

2

=1

a+b=

3

+

2

3

2

+

3

2

3

+

2

=

(

3

+

2

)(

3

2

)

(

3

2

)

2

+(

3

+

2

)

2

=

3−2

5−2

6

+5+2

6

=10

Now, (x+y)

2

=x

2

+y

2

+2xy

⇒x

2

+y

2

=(x+y)−2xy

Replace x=a,y=b

a

2

+b

2

=(a+b)

2

−2ab

=(10)

2

−2×1

(x+y)=10 and xy=1

=100−2=98

a

2

+b

2

−5ab=98−5×1

=98−5

=93

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