Question

(a²+b²)x² -2(ac + bd)x +c²+d²=0,has equal roots,then

Answer 1

Answer:

±2((ac+bd)(ac+bd)-(a^2+b^2)(c^2+d^2))/(a^2+b^2)

Step-by-step explanation:

roots are equal

therefore root= ±(4(ac+bd)(ac+bd)-4(a^2+b^2)(c^2+d^2))/2(a^2+b^2)

= ±2((ac+bd)(ac+bd)-(a^2+b^2)(c^2+d^2))/(a^2+b^2)