Question

A2.
the eigen values of A are 2,3,4 then the
eigen values of 3A are​

Answer 1

Answer:

The eigenvectors stay the same. For convenience take the eigenvalue 1 and eigenvector x1. Then, ((A^2) - 3A + 4I) .x1=((1) ^2)x1 - 3.(1.x1)+ 4 (x1) =2.x1. Similarly the others.

this is the answer

stay safe and happy