Question

A2 The sum of three consecutive multiples of 8
is equal to eight times the sum of the first two
consecutive multiples of 6. Find each of the three
multiples of​

Answer 1

Answer:

first two consecutive multiples of 6=6,12

let three consecutive multiples of 8 = x-8,x,x+8

x-8+x+x+8=8(6+12)

3x = 8×18

x = 48

therefore

three consecutive multiples of 8 are 40 , 48 and 56

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