Question

a²÷x-b²÷y=0
a²b÷x+b²a÷y=a+b

Answer 1

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A²/x-b²/y=0---------1

a²b/x+b²a/y=a+b---2

Now from eq. 2,

=> ab(a/x+b/y)=a+b

=> a/x+b/y=a+b/ab ----- x b ( multiplying b)

=> ab/x+b²/y=a+b/a (after = b&b gets cancelled as one was in numerator and one was in denominator)

Equating eqs. 1 & 2,

a²/x-b²/y=0

ab/x+b²/y=a+b/a

----------------------------

=> a²/x + ab/x= 0 + a+b/a

=> a²+ab/x=a+b/a

=> a(a+b/x)=a+b/a. (a+b & a+b gets cancelled)

=> x=a²

Therefore, x=a² (ans)

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