Question

a2/x - b2/y=0
a2b/x + b2a/y = a+b
solve and find x and y

Answer 1

$first\ equation:\\\\ \frac{a^2}{x}- \frac{b^2}{y}=0\\ or\ \ \ \frac{a^2}{x}=\frac{b^2}{y}\\\\second\ equation:\\\\ \frac{a^2b}{x}+ \frac{b^2a}{y}=a+b\\ \\ \Rightarrow (\frac{b^2}{y}) \times b+ \frac{b^2a}{y}=a+b\\ \\ \Rightarrow (\frac{b^2}{y}) \times (b+a)=a+b\\ \\ \Rightarrow \frac{b^2}{y} = \frac{a+b}{a+b}=1\\ \\ \Rightarrow y=b^2$

$\frac{a^2}{x}=\frac{b^2}{y}\\\\ \Rightarrow \frac{a^2}{x}=\frac{b^2}{b^2}=1\\\\ \Rightarrow x=a^2$

Hence x=a² and y=b²

Answer 2

Answer:

See the attachment...

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