Math, asked by lathatmenon, 1 year ago

a20 - a12 = -32
Arithmatic progression question

Answers

Answered by ShuchiRecites
12

Arithmetic Progression

20th term = a + 19d

12th term = a + 11d

→ (a + 19d) - (a + 11d) = - 32

→ a + 19d - a - 11d = - 32

→ 8d = - 32

→ d = - 4

Verification

→ a + 19(- 4) - a - 11(- 4) = 32

→ a - 76 - a + 44 = 32

→ - 32 = - 32

L.H.S = R.H.S

Hence value of common difference is - 4.

Answered by BrainlyVirat
14

Answer: d = -4

Step by step explanation:

Given that:

  • a20 - a12 = -32

We know that,

  \tt{a_n = a + (n - 1) d}

a20 = a + (20 - 1) d

a20 = a + 19d.. (1)

Similarly,

a12 = a + 11d.. (2)

From eq. (1) and (2),

(a + 19d) - (a + 11d) = -32

8d = -32

Dividing both sides by 8,

  • d = -4

Thus, Value of d is -4.

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